Vi regner ut hvert uttrykk for seg.

$10^{-1}$

$$10^{-1} = \frac{1}{10} = 0{,}1$$

$3^{-2}$

$$3^{-2} = \frac{1}{3^2} = \frac{1}{9} \approx 0{,}111$$

$\dfrac{1}{2^3}$

$$\frac{1}{2^3} = \frac{1}{8} = 0{,}125$$

$\sqrt{81}$

$$\sqrt{81} = 9$$

$2 \cdot 2^4$

$$2 \cdot 2^4 = 2^1 \cdot 2^4 = 2^{1+4} = 2^5 = 32$$

$10^2$

$$10^2 = 100$$

$\sqrt{10^6}$

$$\sqrt{10^6} = (10^6)^{\frac{1}{2}} = 10^{6 \cdot \frac{1}{2}} = 10^3 = 1000$$

Vi har nå:

Uttrykk	Verdi
$10^{-1}$	$0{,}1$
$3^{-2}$	$\approx 0{,}111$
$\dfrac{1}{2^3}$	$0{,}125$
$\sqrt{81}$	$9$
$2 \cdot 2^4$	$32$
$10^2$	$100$
$\sqrt{10^6}$	$1000$

Stigende rekkefølge:

$$\underline{\underline{10^{-1} < 3^{-2} < \frac{1}{2^3} < \sqrt{81} < 2 \cdot 2^4 < 10^2 < \sqrt{10^6}}}$$