Regn ut integralet

$$\int _{0}^1 (4x^2+3) \, dx$$

Fasit

$\frac{13}{3}$

Løsningsforslag

$$\int_{0}^{1} 4x^2+3 \, \mathrm{d}x =\left[ \frac{4}{3}x^3+3x \right]_{0}^{1}=\frac{4}{3}+3\cdot1-0=\frac{4}{3}+\frac{9}{3}=\underline{\underline{\frac{13}{3} }}$$